Explore Herstein through 2 example sentences from English. Ideal for language learners, writers and word enthusiasts.
Herstein in a sentence
Context around Herstein
- Average sentence length in these examples: 38 words
- Position in the sentence: 1 start, 1 middle, 0 end
- Sentence types: 2 statements, 0 questions, 0 exclamations
Corpus analysis for Herstein
- In this selection, "herstein" usually appears near the start of the sentence. The average example has 38 words, and this corpus slice is mostly made up of statements.
- Around the word, non and 1975 stand out and add context to how "herstein" is used.
- Recognizable usage signals include herstein 1975 2 and of r herstein non commutative. That gives this page its own corpus information beyond isolated example sentences.
- By corpus frequency, "herstein" sits close to words such as aabc, aacr and aacsb, which helps place it inside the broader word index.
Example types with herstein
The same corpus examples are grouped by length and sentence type, making it easier to see the contexts in which the word appears:
Herstein 1975, §2.6, p. 54 Two symmetries are combined by composing them as functions, that is, applying the first one to the square, and the second one to the result of the first application. (35 words)
Every simple R-module is isomorphic to a quotient R/m where m is a maximal right ideal of R. Herstein, Non-commutative Ring Theory, Lemma 1.1.3 By the above paragraph, any quotient R/m is a simple module. (41 words)
Every simple R-module is isomorphic to a quotient R/m where m is a maximal right ideal of R. Herstein, Non-commutative Ring Theory, Lemma 1.1.3 By the above paragraph, any quotient R/m is a simple module. (41 words)
Herstein 1975, §2.6, p. 54 Two symmetries are combined by composing them as functions, that is, applying the first one to the square, and the second one to the result of the first application. (35 words)
Example sentences (2)
Every simple R-module is isomorphic to a quotient R/m where m is a maximal right ideal of R. Herstein, Non-commutative Ring Theory, Lemma 1.1.3 By the above paragraph, any quotient R/m is a simple module.
Herstein 1975, §2.6, p. 54 Two symmetries are combined by composing them as functions, that is, applying the first one to the square, and the second one to the result of the first application.